November 1, 2008

物理-1 心得

tanθ = y/x = [VyT + 1/2aT*2] / Vxt

另解: 設邊長為 [ ]n 用[ ]n/vx = T 代入另外一個方程式

結論 連結 幾何圖形,觀念解題。

求邊長?
1.三角函數解最棒 [阿賢敎得]
2.本人=>爛解法( [vxt]*2 + [1/2At*2]*2 )的開二次方根號。

0推薦此文章
Today's Visitors: 0 Total Visitors: 29
Personal Category: ----------文章------------ Topic: learning / academic / Science
[Trackback URL]

Post A Comment









Yes No



Please input the magic number:

( Prevent the annoy garbage messages )
( What if you cannot see the numbers? )
Please input the magic number

誰來收藏
Loading ...
unlog_NVPO 0